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Section 4.8[ATTACH=full]1189[/ATTACH]Question 38I see a right triangle.Let one leg = 160Let the other leg = 85Let x = our bearingtan x = 85/160arctan(tan x) = arctan (85/160)x = 27.98°You say?
Section 4.8
[ATTACH=full]1189[/ATTACH]
Question 38
I see a right triangle.
Let one leg = 160
Let the other leg = 85
Let x = our bearing
tan x = 85/160
arctan(tan x) = arctan (85/160)
x = 27.98°
You say?
