Applying Trigonometric Identities...1

[nycmathguy]

Section 4.3

Can you do 39 as a guide for me to do a few more?

 

[MathLover1]

39.
cos(theta)=1/3

you now that cos(theta)=adj/hyp

so, in this case adj=1 and hyp=3

to find sin(theta)=opp/hyp, use adj=1 and hyp=3

opp=sqrt(3^2-1^2)=sqrt(8)=2sqrt(2)

sin(theta)=(2sqrt(2))/3

tan(theta)=opp/adj=2sqrt(2)/1=2sqrt(2)

cot(theta)=1/tan(theta)= 1/(2sqrt(2))

sec(theta)=1/cos(theta)=1/(1/3)=3

csc(theta)=1/sin(theta)=1/((2sqrt(2))/3)=3/(2sqrt(2))

 

[nycmathguy]

39.
cos(theta)=1/3

you now that cos(theta)=adj/hyp

so, in this case adj=1 and hyp=3

to find sin(theta)=opp/hyp, use adj=1 and hyp=3

opp=sqrt(3^2-1^2)=sqrt(8)=2sqrt(2)

sin(theta)=(2sqrt(2))/3

tan(theta)=opp/adj=2sqrt(2)/1=2sqrt(2)

cot(theta)=1/tan(theta)= 1/(2sqrt(2))

sec(theta)=1/cos(theta)=1/(1/3)=3

csc(theta)=1/sin(theta)=1/((2sqrt(2))/3)=3/(2sqrt(2))

I will try a few tomorrow and post here.