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the area of the rectangle isA=L*Wfrom the graph we see that L=10W=y coordinate of the (x,y)since y=sqrt(36-x^2), we haveA=10*sqrt(36-x^2)domain:{x element R : -6<=x<=6}
the area of the rectangle is
A=L*W
from the graph we see that L=10
W=y coordinate of the (x,y)
since y=sqrt(36-x^2), we have
A=10*sqrt(36-x^2)
domain:
{x element R : -6<=x<=6}