To factorize ax^2−b^2, we use the difference of squares formula:
ax^2−b^2=(x√a−b)(x√a+b).
Given that ax^2−b^2=9x2−4,
we identify a=9 and b=2.
This expression can be factored as (3x−2)(3x+2).
For 9x^2−4 to reduce to 3x−2, the denominator must contain a factor of 3x+2.
So, it should be of the form (3x+2)(4x−1)=12x^2+5x−2.
Thus, the fraction becomes 9x^2−4/12x^2+5x−2, where a=9, b=2, c=12, d=5, and e=−2.
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