Circle O

[nycmathguy]

How about a little geometry for old times?

 

[MathLover1]

note that AB=2OC
if OC=6 then
AB=12
AO=6
OB=6=> triangle COB is right triangle

then (BC)^2=(OC)^2+(OB)^2=6^2+6^2=2*36
BC =sqrt(2*36)=6sqrt(2)

 

[nycmathguy]

note that AB=2OC
if OC=6 then
AB=12
AO=6
OB=6=> triangle COB is right triangle

then (BC)^2=(OC)^2+(OB)^2=6^2+6^2=2*36
BC =sqrt(2*36)=6sqrt(2)

Exactly the same answer I got on paper. I just forgot to upload my work here.