Determine An Inverse Function...2

[nycmathguy]

Section 1.9
Question 68

f(x) = sqrt{x - 2}

Let f(x) = y

y = sqrt{x - 2}

x = sqrt{y - 2}

x^2 = [sqrt{y - 2}]^2

x^2 = y - 2

x^2 + 2 = y

Let y = f^(-1) x

f^(-1) x = x^2 + 2

Yes?

 

[MathLover1]

correct

 

[nycmathguy]

correct

Very good. Beach day 2. I gotta relax on my days off. I have a long work week ahead. Working 4 days at 12 hours per day.