Section 2.6 Question 8 [ATTACH=full]484[/ATTACH] f(x) = (2x)/(x^2 - 4) Set x^2 - 4 to zero and solve for x. x^2 - 4 = 0 x^2 = 4 sqrt{x^2} = sqrt{4} x = -2, x = 2. Domain = ALL REAL NUMBERS except for x = -2 and x = 2. I say the two x-values are the vertical asymptotes. Discuss the behavior of f near the excluded values of x. Limit of f(x) as x tends to -2 from the right side is positive infinity. Limit of f(x) as x tends to 2 from the left side is negative infinity. [ATTACH=full]485[/ATTACH] You say?