Express Logs In Terms of a, b, and c

Discussion in 'Algebra' started by nycmathguy, Jun 18, 2022.

  1. nycmathguy

    nycmathguy

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    IMG_20220618_101412.jpg

    IMG_20220618_101423.jpg
     
    nycmathguy, Jun 18, 2022
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  2. nycmathguy

    MathLover1

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    1. correction

    log((100A^2)/(B^4*C^(1/3)))
    (log((10^2)+log(A^2))-(log(B^4)+log(C^(1/3)))
    (2log((10)+2log(A))-(4log(B)+(1/3)log(C))
    2log((10)+2log(A)-4log(B)-(1/3)log(C)
    2*1+2*a-4*b-(1/3)*c
    2+2a-4b-(1/3)c
    2 a - 4 b - c/3 + 2

    2. correct
    just simplify 5log(4)=5log(2^2)=5*2log(2) =10log(2)
     
    MathLover1, Jun 18, 2022
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  3. nycmathguy

    nycmathguy

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    It's hard not to make a mistake on the first problem.
    In terms of simplifying 5log_10 (4) or 5 times log sub 10 of 4, are you sure this simplifies to 10log(2)?
     
    nycmathguy, Jun 18, 2022
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  4. nycmathguy

    MathLover1

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    yes, as I stated above
    5log_10 (4) =5log_10 (^2) =5*2log_10 (2) =10_10log(2)
     
    MathLover1, Jun 18, 2022
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  5. nycmathguy

    nycmathguy

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    Ok. Thanks. A little precalculus review. Believe it or not, I miss precalculus.
     
    nycmathguy, Jun 18, 2022
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