Find A & B

How about one more tonight?
Is this an important skill to have for Calculus ll?

 

yes it is, everything in math is important

Algebra I skills are crucial to later math courses, and you must master skills like solving systems of equations, graphing, slope, and simplification of radicals. Even in Calculus, most problems consist of one difficult step, followed by ten steps of Algebra.

 

I can do this. I will try first.

 

restricted values of x are: x=3, x=-3



denominators same, so we have



substitute x=3





6B=42
B=7

substitute x=-3



12=-6A
A=-2

 

I thank you very much. However, I did promise to try solving for A and B myself. Please, keep in mind that I work 40 overnight hours. Sleeping during the day is not easy at all. I look like a zombie most of the time.

The weekend hours fly by. Life often gets in the way. I am not lazy. I am committed to improving certain math skills, if not all. I just need time but time runs away from me, from all of us.

 

Another way to do this is to actually add the fractions on the right. $\frac{A}{x+ 3}+ \frac{B}{x- 3}= \frac{A(x- 3)}{(x-3)(x+ 3)}+ \frac{B(x+ 3)}{(x- 3)(x+ 3)}= \frac{Ax- 3A+ Bx+ 3B}{(x- 3)(x+ 3)}= \frac{(A+ B)x- 3A+ 3B}{(x- 3)(x+ 3)}$.
As far as "Calculus II" is concerned, t

 

Sounds good.