Find Area for Value of a

[nycmathguy]

Section 4.7

Just do (a). I will use your reply to do the rest. Thanks.

 

[MathLover1]

a)

a=0
b=1
area=arctan(1)-arctan(0)
area=π/4-0
area=π/4

 

[nycmathguy]

a)

a=0
b=1
area=arctan(1)-arctan(0)
area=π/4-0
area=π/4

I am embarrassed. It is so simple. I will do the rest and show my work.

 

[nycmathguy]

a)

a=0
b=1
area=arctan(1)-arctan(0)
area=π/4-0
area=π/4

I will do the set up. Just tell me if the set up is right for parts (b) through (d).

Part (b)

Let A = area

A = arctan(1)-arctan(-1)

Yes?

Part (c)

A = arctan(3)-arctan(0)

Yes?

Part (d)

A = arctan(3)-arctan(-1)

Yes?

 

[MathLover1]

yes

 

[nycmathguy]

yes

Perfect.