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Calculus
Section 1.6
Can you do 59 as a guide for me to do 60?
Section 1.6
Can you do 59 as a guide for me to do 60?
lim((f(x)-8)/(x-1), x->1)=10, find lim(f(x)) as x->1
use quotient rule
lim((f(x)-8), x->1)/lim(x-1, x->1)=10
lim((f(x)-8), x->1)=10*lim(x-1, x->1)..........for left side use difference rule
lim((f(x), x->1)- lim(8, x->1)=10*lim(x-1, x->1)............lim(8, x->1)=8
lim((f(x), x->1)-8=10*lim(x-1, x->1)......lim(x-1, x->1)=0
lim((f(x), x->1)=10*0+8
lim((f(x), x->1)=8
lim((f(x)-8)/(x-1), x->1)=10, find lim(f(x)) as x->1
use quotient rule
lim((f(x)-8), x->1)/lim(x-1, x->1)=10
lim((f(x)-8), x->1)=10*lim(x-1, x->1)..........for left side use difference rule
lim((f(x), x->1)- lim(8, x->1)=10*lim(x-1, x->1)............lim(8, x->1)=8
lim((f(x), x->1)-8=10*lim(x-1, x->1)......lim(x-1, x->1)=0
lim((f(x), x->1)=10*0+8
lim((f(x), x->1)=8
if lim (f(x)/x^2)=5 as x->0, find following limits
use quotient rule
so, lim (f(x))/lim(x^2)=5 as x->0
a.
lim (f(x))/lim(x^2)=5
lim (f(x))=5 lim(x^2) .....as x->0
lim (f(x))=5 lim(0^2) =5*0=0
b.
lim (f(x)/x) as x->0
lim (f(x)/x)=lim (f(x))/lim(x) ...as x->0
substitute lim (f(x))=0...as x->0
lim (f(x))/lim(x) ...as x->0=lim 0/lim(0)=0