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Two positive numbers are in the ratio 3:4. The sum of thrice the first number and twice the second is 68. Find the smaller number.
Let me see.
3(3x) + 2(4x) = 68
9x + 8x = 68
17x = 68
x = 68/17
x = 4
3x = 3(4) = 12
4x = 4(4) = 16
The smaller number is 12.
Let me see.
3(3x) + 2(4x) = 68
9x + 8x = 68
17x = 68
x = 68/17
x = 4
3x = 3(4) = 12
4x = 4(4) = 16
The smaller number is 12.