Find tan(u + v)

[nycmathguy]

Section 5.4

 

[MathLover1]

correct

just rationalize to eliminate sqrt(3) in denominator

=(1+sqrt(3))/(1-sqrt(3))......rationalize

=(1+sqrt(3))^2/((1-sqrt(3))(1+sqrt(3)))

=(1+sqrt(3))^2/((1-(sqrt(3))^2))

=(1+sqrt(3))^2/(1-3)

=-(1+sqrt(3))^2/2
=-2 (2 + sqrt(3))/2
=-2 - sqrt(3)

 

[nycmathguy]

correct

just rationalize to eliminate sqrt(3) in denominator

=(1+sqrt(3))/(1-sqrt(3))......rationalize

=(1+sqrt(3))^2/((1-sqrt(3))(1+sqrt(3)))

=(1+sqrt(3))^2/((1-(sqrt(3))^2))

=(1+sqrt(3))^2/(1-3)

=-(1+sqrt(3))^2/2
=-2 (2 + sqrt(3))/2
=-2 - sqrt(3)

Perfect. I will do at least 2 more today.

 

[nycmathguy]

correct

just rationalize to eliminate sqrt(3) in denominator

=(1+sqrt(3))/(1-sqrt(3))......rationalize

=(1+sqrt(3))^2/((1-sqrt(3))(1+sqrt(3)))

=(1+sqrt(3))^2/((1-(sqrt(3))^2))

=(1+sqrt(3))^2/(1-3)

=-(1+sqrt(3))^2/2
=-2 (2 + sqrt(3))/2
=-2 - sqrt(3)

Take a look at 22.

 

[MathLover1]

you made mistake with sign, here should be

and result will be:
=2 + sqrt(3)

 

[nycmathguy]

you made mistake with sign, here should be

and result will be:
=2 + sqrt(3)

Ok. I will take credit for all the work. We have already discussed sign errors. On a CUNY test, this question is worth 5 or 6 points. In terms of the sign error, professors will deduct about 3 points.