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Elementary College GeometryQuestion 3 Page 7[ATTACH=full]465[/ATTACH]AB = BC3(x - 15) = x + 33x - 45 = x + 33x - x = 3 + 452x = 48(1/2)(2x) = (1/2)(48)x = 24AC = AB + BCAC = 3(x - 15) + x + 3Let x = 24AC = 3(24 - 15) + 24 + 3AC = 3(9) + 27AC = 27 + 27AC = 54
Elementary College Geometry
Question 3 Page 7
[ATTACH=full]465[/ATTACH]
AB = BC
3(x - 15) = x + 3
3x - 45 = x + 3
3x - x = 3 + 45
2x = 48
(1/2)(2x) = (1/2)(48)
x = 24
AC = AB + BC
AC = 3(x - 15) + x + 3
Let x = 24
AC = 3(24 - 15) + 24 + 3
AC = 3(9) + 27
AC = 27 + 27
AC = 54
