[ATTACH=full]329[/ATTACH]
x-y=4.........eq.1 4x+y=-9........eq.2 xz+yz=60........eq.3 -------------------------------- x-y=4.........eq.1, solve for x x=4+y........eq.1a 4x+y=-9........eq.2, solve for x x=-9/4-y/4........eq.2a from eq.1a and eq.2a we have 4+y=-9/4-y/4.......... solve for y y/4+y=-9/4-4 5y/4=-9/4-16/4 5y/4=-25/4 5y=-25 y=-5 go to x-y=4.........eq.1, substitute y x-(-5)=4 x+5=4 x=4 -5 x=-1 go to xz+yz=60........eq.3, substitute y and x -1*z-5z=60 -6z=60 z=60/-6 z=-10 so, x=-1, y=-5, z=-10 then find (x+y+z)/-2 =(-1-5-10)/-2 (x+y+z)/-2 =(-16)/-2 (x+y+z)/-2 =8