Finding the roots of a 6-degree polynomial

[ZeroKool007]

Hello,
I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

Qx amd mx are defined values, Fx is the variable. Fx^6 and Fx^2 are the degree polynomial...Fx^5, Fx^4, Fx^3, Fx^1 are multiply by 0.

Example: mx=6.3, Qx=0.4 ... this would give the results of
A = 0.4890380
B = 0.788825-0.86129i
C = 0.788825+0.86129i

Thanks,
ZeroKool

 

[Country Boy]

There is no general method of solving a sixth degree polynomial equation. In fact, it was proved, over 100 years ago, that for n> 4 there exist polynomial equations with solutions that can not be written as roots so no formula, similar to the quadratic and cubic formulas can exist for n> 4.