Graph of Cube Root {x}

[nycmathguy]

Set 1.5
Question 40

See attachment.

Do (a), (b), and (c).

 

[MathLover1]

a) given

=> x=2

then

=> approximately y=1.3

b)
given

=> x=5

then

=> y=1.7 (approximately )

c)
given

=>x=6.5

y=

=>y= 1.9 (approximately )

 

[nycmathguy]

a) given

=> x=2

then

=> approximately y=1.3

b)
given

=> x=5

then

=> y=1.7 (approximately )

c)
given

=>x=6.5

y=

=>y= 1.9 (approximately )

Very good. Can this be done without a calculator? I don't think we had calculators 100 years ago.

 

[MathLover1]

it's hard to do it without a calculator because you need to find a number x which raised to the power of 3 equals 2
only possibility is to take guess of x which must be greater than 1 and less than 2

rule:

1. Estimate a number b
2. Divide a by b. If the number c returned is precise to the desired decimal place, stop.
3. Average b and c and use the result as a new guess
4. Repeat step two

 

[nycmathguy]

it's hard to do it without a calculator because you need to find a number x which raised to the power of 3 equals 2
only possibility is to take guess of x which must be greater than 1 and less than 2

rule:

1. Estimate a number b
2. Divide a by b. If the number c returned is precise to the desired decimal place, stop.
3. Average b and c and use the result as a new guess
4. Repeat step two

In that case, I'll stick to the calculator.