Graphing...1

[nycmathguy]

Section 2.3
Question 9a

Blue line = y_1

Red line = y_2

The lines do not lie on top of each other. I say y_1 does not equal y_2.

You say?

 

[MathLover1]

incorrect,

try again, be careful while typing function in graphing calculator

 

[nycmathguy]

incorrect,

try again, be careful while typing function in graphing calculator

I don't have a graphing calculator. I use desmos for graphing.

 

[MathLover1]

demos is a graphing calculator
note: (x^2+2x-1)/(x+3)=x-1+2/(x+3)

 

[nycmathguy]

demos is a graphing calculator
note: (x^2+2x-1)/(x+3)=x-1+2/(x+3)

In that case, y_1 = y_2.

 

[MathLover1]

yes

 

[nycmathguy]

yes

Red curve = blue curve.

Note: y_1 and y_2 lie on top of each other evenly.