Height of Steeple

Section 4.8
Applications

Please draw the picture that represents the situation described in (21). I will do the math work.

 

for some reason I am having trouble uploading my drawing, and I found this one

you just change angle to 48 degrees

 

I will work on this later this morning. Why did you write 47° 40' and not 48 degrees?

 

I know this involves two equations in two unknowns but I don't know how to set up the equations. Please, set up the equations and I'll take it from there. Thanks.

 

let distance BD be y
and distance DC be h

then

tan(35)=y/50..........eq.1

and

tan(48)=(y+h)/50.....eq.2

 

I can take it from here. Thanks.