How to find an area irregular quadrilateral
- Thread starter Srinivas
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divide irregular quadrilateral into rectangle and right triangle, find areas and add them up
rectangle have the length of 857 and the width of 43
so the area of the rectangle=857*43=36851
one leg of the right triangle (altitude) are 865-43=822 and the other leg is 857
the area of the right triangle= (1/2)822 *857=352227
the area of the irregular quadrilateral=36851+352227=389078
rectangle have the length of 857 and the width of 43
so the area of the rectangle=857*43=36851
one leg of the right triangle (altitude) are 865-43=822 and the other leg is 857
the area of the right triangle= (1/2)822 *857=352227
the area of the irregular quadrilateral=36851+352227=389078
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Interesting. Nice reply.
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That's assuming that the sides labeled "255" and "43" are parallel.
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To split the irregular quadrilateral into a rectangle and a right triangle, you first find the dimensions of each shape.
The rectangle has a length of 857 and a width of 43, so its area is 857 * 43 = 36,851 square units.
For the right triangle, one leg (altitude) is 865 - 43 = 822, and the other leg is 857. Applying the formula for the area of a triangle = (1/2)*base*height
the area of triangle = (1/2)*822*857 = 352,227 square units.
Adding the areas of the rectangle and the right triangle together, the total area of the irregular quadrilateral is 36,851+352,227=389,078 square units.
It is quite difficult to solve such type of problem. Especially you need expert help, whenever you experience such type of problem in your assignment. I would suggest you to visit MathsHomewporkHelp.com for your assignment solution. You can also contact them at +1 (315) 557-6473.
The rectangle has a length of 857 and a width of 43, so its area is 857 * 43 = 36,851 square units.
For the right triangle, one leg (altitude) is 865 - 43 = 822, and the other leg is 857. Applying the formula for the area of a triangle = (1/2)*base*height
the area of triangle = (1/2)*822*857 = 352,227 square units.
Adding the areas of the rectangle and the right triangle together, the total area of the irregular quadrilateral is 36,851+352,227=389,078 square units.
It is quite difficult to solve such type of problem. Especially you need expert help, whenever you experience such type of problem in your assignment. I would suggest you to visit MathsHomewporkHelp.com for your assignment solution. You can also contact them at +1 (315) 557-6473.
