John, Peter and Jane weigh 80, 60 and 50 lbs respectively. John sits 3 ft., Peter sits 5 ft. and Jane sits 6 ft. from the fulcrum on the same side. How far must their 200 lb. father sits from the fulcrum in order to balance them?\n\nThis problem involves 3 people. \n\nFather........f.......John.....Peter......Jane\n\nDistance from father to f = x.\nDistance from John to f = 3.\nDistance from Peter to f = 5.\nDistance from Jane to f = 6.\n\nEquation \n\n400x = 3(80) + 5(60) + 6(50)\n\nYou say?