John, Peter and Jane weigh 80, 60 and 50 lbs respectively. John sits 3 ft., Peter sits 5 ft. and Jane sits 6 ft. from the fulcrum on the same side. How far must their 200 lb. father sits from the fulcrum in order to balance them? This problem involves 3 people. Father........f.......John.....Peter......Jane Distance from father to f = x. Distance from John to f = 3. Distance from Peter to f = 5. Distance from Jane to f = 6. Equation 400x = 3(80) + 5(60) + 6(50) You say?