Limits of Piecewise Functions...6

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Calculus

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In order for the limit to exists, the following must take place:

lim (2x + 8) as x tends -2 from the left = lim (x^2) as x tends to -2 from the right.

Let x = -2.

(2x + 8) = (x^2)

(2(-2) + 8) = (-2)^2

4 = 4

So, I can now say that the limit of f(x) as x tends to -2 is 4.
 


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