Parking Lot

[nycmathguy]

Section 6.2

 

[MathLover1]

The area A of a parallelogram, given two adjacent sides a, b and the angle C between them, is twice the area of the corresponding triangle.
So, use A = ab sin(C)

 

[nycmathguy]

The area A of a parallelogram, given two adjacent sides a, b and the angle C between them, is twice the area of the corresponding triangle.
So, use A = ab sin(C)

Thanks. I can take it from here. Thank you so much for all that you do here to help me understand my favorite course. . . Precalculus.

 

[Country Boy]

Why would you want to find x, the length of a diagonal? The area of a parallelogram is "base times height". here we can take the "base" to be the 100 m long side. The "height" is given by drawing a line from the top of the 70 m long side perpendicular to the 100 m side. The height is the leg of a right triangle, with hypotenuse 70, opposite the 70 degree angle.

 

[nycmathguy]

Why would you want to find x, the length of a diagonal? The area of a parallelogram is "base times height". here we can take the "base" to be the 100 m long side. The "height" is given by drawing a line from the top of the 70 m long side perpendicular to the 100 m side. The height is the leg of a right triangle, with hypotenuse 70, opposite the 70 degree angle.

Brother, if you are going to belittle my effort on every thread, I prefer that you simply skip my questions. This is easy to do.

 

[Country Boy]

Brother, if you are going to belittle my effort on every thread, I prefer that you simply skip my questions. This is easy to do.

I did not "belittle" you, I asked a serious question. I wanted to know your reasoning in this problem.

 

[nycmathguy]

I did not "belittle" you, I asked a serious question. I wanted to know your reasoning in this problem.

Cool.