Planet Mars

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Exercises 1.4

20211009_201335.jpg


For part (a), I must evaluate each interval [a, b] this way:

Let A(t) = average velocity

A(t) = [(10(b) - 1.86(b)^2] - [(10(a) - 1.86(a)^2] ÷ (b - a)

For part (b), I must find derivative of the given function and then evaluate when t = 1.

Yes
 
Exercises 1.4

View attachment 614

For part (a), I must evaluate each interval [a, b] this way:

Let A(t) = average velocity

A(t) = [(10(b) - 1.86(b)^2] - [(10(a) - 1.86(a)^2] ÷ (b - a)

For part (b), I must find derivative of the given function and then evaluate when t = 1.

Yes
Yes, that is what you are to do. Why haven't you done it?
 


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