Radioactive Decay

[nycmathguy]

In example 9, how much of the 10 pounds will remain in the year 2089? How much of
the 10 pounds will remain after 125,000 years?

Here is my set up:

P = 10(1/2)^(t/24,100)

Let me see.

t = 2089 - 1986

t = 103

P = 10(1/2)^(103/24,100)

Yes?

How about 125,000 years?

t = 125,000 - 1986

t = 123,014

P = 10(1/2)^(123,014/24,100)

Correct set up?

 

[MathLover1]

Correct

 

[nycmathguy]

Correct

Thank you.