Show that x -> x^p is an automorphism in K

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Let K be a finite field of characteristic p > 0. Show that s(x) = x^p is an automorphism in K.

It is clear in case K is a prime field, because then s(x) is just an identity. If K is not prime, s(x) is identity on its prime subfield. But how to show the automorphism of s() for the rest of the field, when it's not prime?
 
Abstract algebra was my (easily) least favorite college math course.

Since no one has replied to this yet, perhaps, just to (re-) educate me and others, you might define the terms to clarify the problem.

Thanks.
 


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