C Country Boy Joined Dec 15, 2021 Messages 157 Reaction score 38 Jan 5, 2022 #2 Solve the equations (1/2)n(n- 3)= (1/2)(n^2- 3n)= 65 and (1/2)n(n- 1)= (1/2)(n^2- 3n)= 80. Such polygons exist only if n is a positive integer.
Solve the equations (1/2)n(n- 3)= (1/2)(n^2- 3n)= 65 and (1/2)n(n- 1)= (1/2)(n^2- 3n)= 80. Such polygons exist only if n is a positive integer.
nycmathguy Joined Jun 27, 2021 Messages 5,386 Reaction score 422 Jan 5, 2022 #3 Country Boy said: Solve the equations (1/2)n(n- 3)= (1/2)(n^2- 3n)= 65 and (1/2)n(n- 1)= (1/2)(n^2- 3n)= 80. Such polygons exist only if n is a positive integer. Click to expand... I'll get to this on my days off.
Country Boy said: Solve the equations (1/2)n(n- 3)= (1/2)(n^2- 3n)= 65 and (1/2)n(n- 1)= (1/2)(n^2- 3n)= 80. Such polygons exist only if n is a positive integer. Click to expand... I'll get to this on my days off.