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Section 2.2
Question 76
I can write 76 this way: f(x) = -x^3 + 8 for easy graphing.
Part (a)
According to the Leading Coefficient Test, when the leading coefficient is negative with an odd degree, the graph rises to the left and falls to the right.
Part (b)
The graph crosses the x-axis at the point (2, 0).
So, x = 2 is the only real zero.
Part (c)
x..........f(x)
-2..........16
-1...........9
0............8
1............7
2............0
Part (d)
Question 76
I can write 76 this way: f(x) = -x^3 + 8 for easy graphing.
Part (a)
According to the Leading Coefficient Test, when the leading coefficient is negative with an odd degree, the graph rises to the left and falls to the right.
Part (b)
The graph crosses the x-axis at the point (2, 0).
So, x = 2 is the only real zero.
Part (c)
x..........f(x)
-2..........16
-1...........9
0............8
1............7
2............0
Part (d)