Slopes & Numbers

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Set 1.6

Can you do 12 a and b? Explain how this is done.
Thank you.

20210917_193816.jpg
 
m1, m2, and m3 are slopes

as you can see, blue line has negative slope (most of it passes through II and IV quadrant)=> m3 is negative and should be smallest slope
m1 and m2 are positive
the greater the slope, the steeper the line
in your case the black line is steeper then red one; so, m1> m2

then, slopes in increasing order are: m3,m2,m1

b1,b2,b3 are y-intercepts
black line has negative y-intercept->b1 <0

red line has positive y-intercept
blue line has positive y-intercept

b3 is above b2 =>b3>b2

in increasing order : b1, b2, b3
 
m1, m2, and m3 are slopes

as you can see, blue line has negative slope (most of it passes through II and IV quadrant)=> m3 is negative and should be smallest slope
m1 and m2 are positive
the greater the slope, the steeper the line
in your case the black line is steeper then red one; so, m1> m2

then, slopes in increasing order are: m3,m2,m1

b1,b2,b3 are y-intercepts
black line has negative y-intercept->b1 <0

red line has positive y-intercept
blue line has positive y-intercept

b3 is above b2 =>b3>b2

in increasing order : b1, b2, b3

You said:

b3 is above b2 =>b3>b2
in increasing order : b1, b2, b3
.


What is this?
 
I don't know how that happened, probably coding this site use messed up with my response


m1, m2, and m3 are slopes

as you can see, blue line has negative slope (most of it passes through II and IV quadrant)=> m3 is negative and should be smallest slope
m1 and m2 are positive
the greater the slope, the steeper the line
in your case the black line is steeper then red one; so, m1> m2

then, slopes in increasing order are: m3,m2,m1

b1,b2,b3 are y-intercepts
black line has negative y-intercept -> b1 < 0
red line has positive y-intercept
blue line has positive y-intercept

b3 is above b2 => b3 > b2
in increasing order : b1, b2, b3
 
I don't know how that happened, probably coding this site use messed up with my response


m1, m2, and m3 are slopes

as you can see, blue line has negative slope (most of it passes through II and IV quadrant)=> m3 is negative and should be smallest slope
m1 and m2 are positive
the greater the slope, the steeper the line
in your case the black line is steeper then red one; so, m1> m2

then, slopes in increasing order are: m3,m2,m1

b1,b2,b3 are y-intercepts
black line has negative y-intercept -> b1 < 0
red line has positive y-intercept
blue line has positive y-intercept

b3 is above b2 => b3 > b2
in increasing order : b1, b2, b3

Much better. Can you take a look at two unanswered questions in this Algebra forum?
 

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