Solve for x

Discussion in 'Algebra' started by nycmathguy, Jul 4, 2022.

  1. nycmathguy

    nycmathguy

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    Solve x^3(x^2 - 5) = -4x
     
    nycmathguy, Jul 4, 2022
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  2. nycmathguy

    MathLover1

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    x^3(x^2 - 5) = -4x
    x^5 - 5x^3 = -4x
    x^5 - 5x^3 +4x=0
    (x^4 - 5x^2 +4)x=0

    => one solution is x=0

    x^4 - 5x^2 +4=0 ...........factor
    x^4 - x^2 -4x^2+4=0
    (x^4 - x^2) -(4x^2-4)=0
    x^2(x^2 - 1) -4(x^2-1)=0
    (x^2-4)(x^2-1)=0
    (x^2-2^2)(x^2-1)=0
    (x - 2) (x + 2) (x - 1) (x + 1)= 0

    => other solutions are x=2, x=-2, x=1, x=-1

    combine solutions: x=0, x=2, x=-2, x=1, x=-1

    [​IMG]

     
    MathLover1, Jul 4, 2022
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    This one is a nasty problem.
     
    nycmathguy, Jul 4, 2022
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