Solve for y

[nycmathguy]

Revisiting precalculus just for fun.

 

[MathLover1]

(x*x1)/a^2=(y*y1)/b^2=1

since you need y, do only this part

(y*y1)/b^2=1
y*y1=b^2
y=b^2/y1

 

[nycmathguy]

(x*x1)/a^2=(y*y1)/b^2=1

since you need y, do only this part

(y*y1)/b^2=1
y*y1=b^2
y=b^2/y1

Algebra is better than crossword puzzles.