[ATTACH=full]671[/ATTACH] For x^3- 2x^2 - 3x = 0, I can factor out x. x(x^2 - 2x - 3) = 0 I set each factor to 0. The first is just x = 0. The second factor becomes (x - 3)(x + 1). Setting each factor to 0, I get x = -1, x = 3. There are three zeros: x = -1, x = 0, x = 3. The second problem is a 4th degree polynomial. What is the easiest way to solve for x? I say graphing is the easiest approach. Is there a general formula, similar to the quadratic formula, for solving any polynomial equation? You say?