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David Cohen questions just for fun.
Enjoy.
Enjoy.
sqrt(2)x -sqrt(3)y=sqrt(3)..........1)
sqrt(3)x -sqrt(8)y=sqrt(2)............2)
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sqrt(2)x -sqrt(3)y=sqrt(3)..........1), solve for y
sqrt(2)x -sqrt(3)=sqrt(3)y
sqrt(2)x/sqrt(3) -sqrt(3)/sqrt(3)=y
sqrt(2)x/sqrt(3) -1=y
y=(sqrt(2)/sqrt(3))*x -1...............1a)
go to
sqrt(3)x -sqrt(8)y=sqrt(2)............2), substitute y
sqrt(3)x -2sqrt(2)((sqrt(2)/sqrt(3))*x -1)=sqrt(2)........ solve for x
sqrt(3)x -(2sqrt(2)sqrt(2)/sqrt(3)))x =sqrt(2)-2sqrt(2)
sqrt(3)x -(4/sqrt(3)))x =-sqrt(2)
(sqrt(3) -4/sqrt(3))x =-sqrt(2)
(-sqrt(3)/3)x =-sqrt(2)
x =-sqrt(2)/(-sqrt(3)/3)
x =sqrt(6)
go to
y=(sqrt(2)/sqrt(3))*x -1...............1a), substitute x
y=(sqrt(2)/sqrt(3))*sqrt(6) -1
y=2-1
y=1