Solving Trigonometric Equations...5

[nycmathguy]

Section 5.3

 

[MathLover1]

30.
general solutions are correct

x=pi/3+2pi*k
x=5pi/3+2pi*k

but, you need solutions for the range 0<=x<=2pi (given interval [0,2pi]) and solutions are
x=pi/3
x=5pi/3
Degrees:
x=60°
x=300°

32.
in interval [0,2pi]) solutions are
Radians:
x=0
x=2pi

Degrees:
x=0°
x=360°

 

[nycmathguy]

30.
general solutions are correct

x=pi/3+2pi*k
x=5pi/3+2pi*k

but, you need solutions for the range 0<=x<=2pi (given interval [0,2pi]) and solutions are
x=pi/3
x=5pi/3
Degrees:
x=60°
x=300°

32.
in interval [0,2pi]) solutions are
Radians:
x=0
x=2pi

Degrees:
x=0°
x=360°

1. Are you saying that [0, 2•pi) means all solutions in one revolution?

2. Is my general solution correct for 32?

 

[MathLover1]

yes

 

[nycmathguy]

yes

Very good. Time for Christmas music while working on some trigonometric equations. New questions posted soon.