Word Problem for number Four {4}

[Krishna]

चारले चारलाई चार चोटि चार गुणा गर्नुहोस. [..There is a four called four-A, and another four called four-B. Now, you have to multiply firt four, four-A by second four, four-B, by four times. What would be the resulting number?..] note= four is a number four {4}

 

[HallsofIvy]

I am not at all clear what you are saying! A "four" is a "four" whether you call it "four-A" or "four-B". Multiplying "four-A" by "four-B", four times is 4(4)(4)(4)(4)= 4^5= (2^2)^5= 2^10= 1024.

 

[nycmathguy]

I am not at all clear what you are saying! A "four" is a "four" whether you call it "four-A" or "four-B". Multiplying "four-A" by "four-B", four times is 4(4)(4)(4)(4)= 4^5= (2^2)^5= 2^10= 1024.

How on earth did you figure out this madness? This problem makes no sense to me, honestly.