Writing Equations From Graphs...4

Discussion in 'Other Pre-University Math' started by nycmathguy, Aug 1, 2021.

  1. nycmathguy

    nycmathguy

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    Section 1.7
    Question 50

    See attachment.

    50a. The general form is y = a•sqrt{x}.

    Use the given point to find a.

    16 = a•sqrt{4}

    16 = 2a

    16/2 = a

    8 = a

    f(x) = 8•sqrt{x}.

    50b.

    The general form is y = a•sqrt{x}.

    Use the given point to find a.

    -1/2 = a•sqrt{4}

    -1/2 = 2a

    (-1/2)/2 = a

    1/4 = a

    f(x) = (1/4)sqrt{x}.

    20210801_184433.jpg
     
    nycmathguy, Aug 1, 2021
    #1
  2. nycmathguy

    MathLover1

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    correction to this part

    (-1/2)/2 = a -> you are dividing negative number (-1/2) by positive number 2, so quotient will be negative number

    -1/4 = a
    f(x) = -(1/4)sqrt{x}.
     
    MathLover1, Aug 2, 2021
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    It was a typo at my end. Negative ÷ Positive = Negative.
     
    nycmathguy, Aug 2, 2021
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